A car has a steady speed of 25m/s along a horizontal curve of radius 115m. What is the minimum coefficient of static friction between the road and the car’s tires that will allow the car to travel at this speed without sliding?
according to 2 Newton’s law:\text{ according to 2 Newton's law:} according to 2 Newton’s law:
F⃗=m∗a⃗\vec F = m*\vec aF=m∗a
a⃗=v2r\vec a = \frac{v^2}{r}a=rv2
F⃗=m∗v2⃗r\vec F = m*\frac{\vec{ v^2}}{r}F=m∗rv2
also: \text{also: }also:
F⃗=m∗g⃗+N⃗+Ffr⃗\vec F = m*\vec{g}+\vec N +\vec{F_{fr}}F=m∗g+N+Ffr
Horizontal force projections:\text{Horizontal force projections:}Horizontal force projections:
F=Ffr(1)F= F_{fr}(1)F=Ffr(1)
Vertical force projections:\text{Vertical force projections:}Vertical force projections:
N−mg=0N-mg=0N−mg=0
N=mgN= mgN=mg
Ffr=μN=μmgF_{fr} =\mu N=\mu mgFfr=μN=μmg
From equality(1):\text{From equality(1):}From equality(1):
m∗v2⃗r=μmgm*\frac{\vec{ v^2}}{r} = \mu mgm∗rv2=μmg
μ=v2r∗g=252115∗9.8=0.55\mu = \frac{v^2}{r*g}= \frac{25^2}{115*9.8}=0.55μ=r∗gv2=115∗9.8252=0.55
Answer : μ=0.55\text{Answer : }\mu =0.55Answer : μ=0.55
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