Answer to Question #210694 in Classical Mechanics for arslamst

Question #210694

Ms. Ratchford wants to go for a walk. She travels to Starbucks which is 3.5 km [N11W] she then goes to Walmart to get groceries and travels 1.5 KM[S45E]. What is her displacement?


1
Expert's answer
2021-06-25T10:45:15-0400

let:\text{let:}

point O starting point of movement\text{point O starting point of movement}

point S - Starbucks location\text{point S - Starbucks location}

point W - Walmart location\text{point W - Walmart location}

α=(OS,SW)\alpha=\angle(\vec {OS},\vec {SW})

α=[N11W]+(N,E)+[S45E]=146°\alpha= [N11W] +\angle({\vec{N}},{\vec{E}})+ [S45E]=146\degree

OW=OS+SW\vec {OW}= \vec {OS}+\vec {SW}

OW=OS2+SW2+2OSSWcosα|\vec {OW}|=\sqrt{|\vec {OS}|^2+|\vec {SW}|^2+2*|\vec {OS}|*|\vec {SW}|*\cos\alpha}

OW=3.52+1.52+21.53.5cos146°=2.4|\vec {OW}|=\sqrt{3.5^2+1.5^2+2*1.5*3.5*\cos146\degree}=2.4

Aswer: displacement = 2.4 km\text{Aswer: displacement = 2.4 km}



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