Question #208462

The parameters of the spring oscillator shown by the figure are: m = 3 kg and k = 300 N/m. We displace the ball to the left by s = 10 cm from the equilibrium position, then release it. Let us assume there is no loss of energy in the system! Calculate:

a) the natural frequency of the system,

b) the period of the oscillation,

c) the amplitude of the oscillation! 


1
Expert's answer
2021-06-18T11:21:59-0400

a)f=12πkma)f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

f=12π3003=1.59f=\frac{1}{2\pi}\sqrt{\frac{300}{3}}=1.59

f=1.59 Hzf=1.59\ Hz

b)T=1fb) T= \frac{1}{f}

T=11.59=0.63T= \frac{1}{1.59}=0.63

T=0.63 sT=0.63\ s

c)A=sc) A =s

A=0.1 mA =0.1\ m

Answer: a)f=1.59 Hz;b)T=0.63s;c)A=0.1m\text{Answer: } a)f=1.59\ Hz ;b)T=0.63s;c)A=0.1m


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