A 6 L bottle contains 16·1023 N2 molecules. Find the
a) amount of substance and
b) the pressure of the nitrogen gas if its temperature is 0 °C and it is considered ideal.
Could you explain b) in detail please?
a)
ν=NNA=16⋅10236.02⋅1023=2.66 mol,\nu=\frac{N}{N_A}=\frac{16\cdot 10^{23}}{6.02\cdot 10^{23}}=2.66~mol,ν=NAN=6.02⋅102316⋅1023=2.66 mol,
b)
p=νRTV=2.66⋅8.31⋅2730.006=9.9 atm.p=\frac{\nu RT}{V}=\frac{2.66\cdot 8.31\cdot 273}{0.006}=9.9~atm.p=VνRT=0.0062.66⋅8.31⋅273=9.9 atm.
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