Question #206847

A ball (m=0.8 kg) falls to the floor from a height of 2 m and bounces back to a height of 1.2 m. Calculate the amount of energy lost due to air drag and collision with the ground.


Could you please explain it in detail?


Expert's answer

First, find the initial energy, the initial potential energy:


Ei=mghi=0.89.82=15.68 J.E_i=mgh_i=0.8·9.8·2=15.68\text{ J}.

The final energy (after rebounding):


Ef=mghf=0.89.81.2=9.41 J.E_f=mgh_f=0.8·9.8·1.2=9.41\text{ J}.

How much was lost? Right:


EL=EiEf=15.689.41=6.27 J.E_L=E_i-E_f=15.68-9.41=6.27\text{ J}.


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