Question #204493

A string with free boundary caused by stationary waves. The distance of four adjacent nodes is 90cm. If the speed of wave propagation is 45m/s. the frequency of the wave is...


1
Expert's answer
2021-06-08T09:35:48-0400

l=90cm=0.9ml=90cm=0.9m

n=4n=4

λ=ln=0.94=0.225\lambda=\frac{l}{n}=\frac{0.9}{4}=0.225

v=45msv=45\frac{m}{s}

λ=vf\lambda=\frac{v}{f}

f=vλ=450.225=200 Hzf=\frac{v}{\lambda}=\frac{45}{0.225}=200\ Hz

Answer: f=200 Hz\text{Answer: }f=200\ Hz



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