A string with free boundary caused by stationary waves. The distance of four adjacent nodes is 90cm. If the speed of wave propagation is 45m/s. the frequency of the wave is...
l=90cm=0.9ml=90cm=0.9ml=90cm=0.9m
n=4n=4n=4
λ=ln=0.94=0.225\lambda=\frac{l}{n}=\frac{0.9}{4}=0.225λ=nl=40.9=0.225
v=45msv=45\frac{m}{s}v=45sm
λ=vf\lambda=\frac{v}{f}λ=fv
f=vλ=450.225=200 Hzf=\frac{v}{\lambda}=\frac{45}{0.225}=200\ Hzf=λv=0.22545=200 Hz
Answer: f=200 Hz\text{Answer: }f=200\ HzAnswer: f=200 Hz
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