Find the center of mass of twelve identical particles
Let the position of the particle from the origin be r1,r2,r3....r12r_1, r_2, r_3....r_{12}r1,r2,r3....r12
Let the masses of the particles are m1,m2,m3,m4....m12m_1, m_2, m_3, m_4.... m_{12}m1,m2,m3,m4....m12
Hence, center of mass of the system, xcom=m1r1+m2r2+m3r3...m12r12m1+m2+m3....m12x_{com}=\frac{m_1r_1+m_2r_2+m_3r_3...m_{12}r_{12}}{m_1+m_2+m_3....m_{12}}xcom=m1+m2+m3....m12m1r1+m2r2+m3r3...m12r12
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