Bob is riding his bike (combined mass of 90 kg) over a hill, which creates a radius of 30m. He is traveling at a speed of 4 m/s. What is the force he feels from his bike as he is going over the crest of the hill?
F=F1+F2=mg+mv2r=m(g+v2r),F=F_1+F_2=mg+\frac{mv^2}{r}=m(g+\frac{v^2}{r}),F=F1+F2=mg+rmv2=m(g+rv2),
F=90⋅(9.8+4230)=930 N.F=90\cdot (9.8+\frac{4^2}{30})=930~\text N.F=90⋅(9.8+3042)=930 N.
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