(Specific latent heat of fusion of ice = 3.34 x 105 J/kg)
1.
Q=λm=3.34⋅105⋅0.5=167 kJ.Q=\lambda m=3.34\cdot 10^5\cdot 0.5=167~kJ.Q=λm=3.34⋅105⋅0.5=167 kJ.
2.
λ=Qm=6⋅1054=1.5⋅105 Jkg.\lambda=\frac Qm=\frac{6\cdot 10^5}{4}=1.5\cdot 10^5~\frac {J}{kg}.λ=mQ=46⋅105=1.5⋅105 kgJ.
3.
P=Qt ⟹ t=QP=LmP=2.26⋅106⋅0.52200=8.5 min.P=\frac Qt\implies t=\frac QP=\frac{Lm}{P}=\frac{2.26\cdot 10^6\cdot 0.5}{2200}=8.5~min.P=tQ⟹t=PQ=PLm=22002.26⋅106⋅0.5=8.5 min.
4.
Q=λm=3.34⋅105⋅0.3=0.1 MJ.Q=\lambda m=3.34\cdot 10^5\cdot 0.3=0.1~MJ.Q=λm=3.34⋅105⋅0.3=0.1 MJ.
5.
The difference in the transition to the liquid and gaseous phase, respectively.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment