A 360 kg roller coaster car traveling at 18 m/s collides inelastically with a stationary 240 kg car on a section of a horizontal track. To what maximum height, h, do the combined cars travel before rolling back down the hill?
m1v=(m1+m2)u ⟹ u=m1vm1+m2,m_1v=(m_1+m_2)u\implies\\ u=\frac{m_1v}{m_1+m_2},m1v=(m1+m2)u⟹u=m1+m2m1v,
(m1+m2)u22=(m1+m2)gh ⟹ h=u22g=m12v22(m1+m2)2g=5.9 m.\frac{(m_1+m_2)u^2}{2}=(m_1+m_2)gh\implies\\ h=\frac{u^2}{2g}=\frac{m_1^2v^2}{2(m_1+m_2)^2g}=5.9~m.2(m1+m2)u2=(m1+m2)gh⟹h=2gu2=2(m1+m2)2gm12v2=5.9 m.
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