Question

Mike is on a hunting trip but dosent like to shoot at animals so he places a baseball in a tree right above him. Than shoots a bullet (0.02 kg) at the baseball (0.15 kg). The two objects embed and Rose to a max height of 13.5 meters before coming back down. What was the initial velocity of the bullet?

Answer 1

$vm_1=u(m_2+m_2),$

$h=\frac{u^2}{2g}\implies u=\sqrt{2gh},$

$v=\frac{\sqrt{2gh}(m_1+m_2)}{m_1}=138~\frac ms.$