the flow in a lake is 0.5 m ^ 3 / s. a water fall in the lake has a height of 1.5m. with a thermal efficiency of 40%, how much power can be added
P=ηP0=ηAt=ηFht=ηmght=ηρVght=ηρQgh=0.4⋅1000⋅0.5⋅10⋅1.5=3 kW.P=\eta P_0=\frac {\eta A}{t}=\frac{\eta Fh}{t}=\frac{\eta mgh}{t}=\frac{\eta \rho Vgh}{t}=\eta \rho Qgh=0.4\cdot1000\cdot 0.5\cdot 10\cdot 1.5=3~kW.P=ηP0=tηA=tηFh=tηmgh=tηρVgh=ηρQgh=0.4⋅1000⋅0.5⋅10⋅1.5=3 kW.
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