Answer to Question #186225 in Classical Mechanics for Jethro

Question #186225

If a force of 5 lb produces a stretch of one-tenth the natural length L ft of a spring. How much work will be done in stretching the spring to double its natural length?


1
Expert's answer
2021-05-03T10:32:44-0400

F1=kΔx1=kL10    k=10F1L=50L,F_1=k\Delta x_1=k\cdot \frac{L}{10}\implies k=\frac{10F_1}{L}=\frac{50}{L},

F2=kΔx2=kL=50LL=50 lb.F_2=k\Delta x_2=kL=\frac{50}{L}\cdot L=50~\text{lb}.


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