The boy in question 1 now throws his ball horizontally out of a high window with a velocity of 3.1 m s-1. How long will it take to reach the ground 18m below?
vx=3.1 ms, vy=0 ms,v_x=3 .1~\frac ms,~v_y=0~\frac ms,vx=3.1 sm, vy=0 sm,
h=vyt+gt22=gt22 ⟹ h=v_yt+\frac{gt^2}{2}=\frac{gt^2}{2}\impliesh=vyt+2gt2=2gt2⟹
t=2hg=1.9 s.t=\sqrt{\frac{2h}{g}}=1.9~s.t=g2h=1.9 s.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments