Question #185841

The boy in question 1 now throws his ball horizontally out of a high window with a velocity of 3.1 m s-1. How long will it take to reach the ground 18m below?



1
Expert's answer
2021-04-26T16:48:31-0400

vx=3.1 ms, vy=0 ms,v_x=3 .1~\frac ms,~v_y=0~\frac ms,

h=vyt+gt22=gt22    h=v_yt+\frac{gt^2}{2}=\frac{gt^2}{2}\implies

t=2hg=1.9 s.t=\sqrt{\frac{2h}{g}}=1.9~s.


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