A small ball of mass m = 5 kg is suspended from
a string of length L = 5 m. The ball revolves
with constant speed v in a horizontal circle of
radius r = 2 m. Find an expression for v and a.
Answer
By applying equilibrium in vertical
"Tcos\\theta=mg"
And
"Tsin\\theta=\\frac{mv^2}{r}\\\\mgtan\\theta=\\frac{mv^2}{r}\\\\v=\\sqrt{rgtan\\theta}"
This is the required equation of velocity
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