Answer to Question #185592 in Classical Mechanics for Jethro

Question

A particle starts from rest and moves around a fixed point with a constant acceleration of 2 rad.s^-2.

Find its angular velocity after 2 s.

Determine the angular displacement and the number of revolutions it made after 5 s.

Answer 1

Answer

Using

$\omega^2=\omega_0^2+\alpha t$

So its angular velocity after 2 s.

$\omega^2=0+2\times2\\\omega=2rad/sec.$

Angular displacement

$\theta=\frac{\omega^2}{2\alpha}\\=\frac{2^2}{2\times2}=1rad$

No of revolution

=5rad.