Answer to Question #185233 in Classical Mechanics for Darko

Question

Bowling ball that is rolling has a mass of 4kg at a speed of 12m/s and reaches a height of 3.5 meters how much work did friction do?

Answer 1

$v=at,$

$h=\frac{at^2}{2}=\frac{v^2}{2a},$

$a=g-\frac Fm,$

$\frac Fm=g-\frac{v^2}{2h},$

$F=gm-\frac{mv^2}{2h},$

$A=-Fh=\frac{mv^2}{2}-mgh,$

$A=\frac{4\cdot 12^2}{2}-4\cdot 9.8\cdot 3.5=150~J.$