Question

Calculate the kinetic energy of a neutron whose momentum is 200 MeV/c

Answer 1

Answer

The kinetic energy is given by

$K=\frac{P^2}{2m_n}\\=\frac{(200MeV/c)^2}{2\times1.67\times10^{-27}}\\=\frac{(40000\times1.6\times10^{-13})}{2\times1.67\times10^{-27}}$

$=1.92\times10^{18}J$