Question #179357

A car slows from 23.69 m/s to rest in 4.44 s. How far did it travel in this time?


1
Expert's answer
2021-04-09T06:37:57-0400

Answer

Using

v=u+at

0=23.69a×4.44a=5.35m/s20=23.69-a\times4.44\\a=5.35m/s^2

So travelled distance

S=v2u22a=023.6922×5.35=52.45mS=\frac{v^2-u^2}{2a}\\=\frac{0-23.69^2}{-2\times5.35}\\=52.45m



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