How long does it take for a ball dropped off of a building of height 69.2 m to hit the ground if the ball starts it's fall from rest?
Answer
By equation of motion
"S=ut+\\frac{1}{2}gt^2"
Initially u=0m/s
So
"69.2=\\frac{1}{2}(9.81) t^2\\\\t=3.75s"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment