Question

How long does it take for a ball dropped off of a building of height 69.2 m to hit the ground if the ball starts it's fall from rest?

Answer 1

Answer

By equation of motion

$S=ut+\frac{1}{2}gt^2$

Initially u=0m/s

So

$69.2=\frac{1}{2}(9.81) t^2\\t=3.75s$