The amplitude of a lightly damped oscillator decreases by 3.0% during each cycle.After how many oscillations(approximately) will the amplitude drop to its half its initial value
A2=A(1−k100)n,\frac A2=A(1-\frac{k}{100})^n,2A=A(1−100k)n,
12=(1−k100)n,\frac 12=(1-\frac{k}{100})^n,21=(1−100k)n,
n=1log2100100−k=23.n=\frac{1}{log_2\frac{100}{100-k}}=23.n=log2100−k1001=23.
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