A baseball player bats the ball at 60° with the ground at a velocity of 50m/s-1. A fielder immediately runs in the opposite direction at a speed of 7m/s-1 in time to catch the ball.
Calculate the distance travelled by the fielder.
t=2vsinαg,t=\frac{2v sin \alpha}{g},t=g2vsinα,
l=Vt=2Vvsinαg,l=Vt=\frac{2Vv sin \alpha}{g},l=Vt=g2Vvsinα,
l=2⋅7⋅50⋅0.879.8=62 m.l=\frac{2\cdot 7\cdot 50\cdot 0.87}{9.8}=62~m.l=9.82⋅7⋅50⋅0.87=62 m.
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