Question #173133
A ball with mass 1kg suspended on a spring oscillates nutritionally with the amplitude A = 10cm and period T = 3s.Determine the kinetic and potential energy of the ball when it is deviated from the equilibrium position at a distance x = A/2
1
Expert's answer
2021-03-21T11:31:37-0400
E=0.5mv2=0.5mω2A2E=m4π2T2A2E=14π2320.12=0.0439 JE=0.5mv^2=0.5m\omega^2A^2\\E=m\frac{4\pi^2}{T^2}A^2\\E=1\frac{4\pi^2}{3^2}0.1^2=0.0439\ J

K=14π2320.052=0.0110 JU=0.04390.011=0.0329 J\\K=1\frac{4\pi^2}{3^2}0.05^2=0.0110\ J\\U=0.0439-0.011=0.0329\ J


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