A particle f mass 5kg is moving in anticlockwise direction with aspect of 3m/s ina circular path of radius 10cm.Find the angle moving of this particle with respect to the centre of the path?
v=ω∗r where ω−angular velocity;v=\omega*r \text{ where }\omega-\text{angular velocity};v=ω∗r where ω−angular velocity;
ω=vr=30.1=30\omega= \frac{v}{r}=\frac{3}{0.1}=30ω=rv=0.13=30
θ(t)=ω∗t=30t where θ−counterclockwise rotation angle\theta(t)= \omega*t = 30t\text{ where }\theta- \text{counterclockwise rotation angle}θ(t)=ω∗t=30t where θ−counterclockwise rotation angle
or θ(t)=−30t where θ−clockwise rotation\text{or }\theta(t) = -30t\text{ where }\theta- \text{clockwise rotation}or θ(t)=−30t where θ−clockwise rotation
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