Question

A boy on board a cruise ship drops a 30.0 gm marble into the ocean. If the

resistive force proportionality constant is 0.500 kg/s, what is the terminal speed

of the marble in m/s?

Answer 1

$F=mg,\\ v=\frac Fk=\frac{mg}{k},\\ v=\frac{0.03\cdot 9.81}{0.5}=0.589~\frac{\text{m}}{\text{s}}.$