A projectile is fired at an angle αwith initial velocity v0. If it experiences the
resistive force 𝐹𝑟 = −𝑘𝑣
2
, find the expression for distance covered x as a
function of vx ant time. Also discuss the special cases.
Answer
For projectile motion
"u_x=v_0cos\\alpha"
"u_y=v_0sin\\alpha"
Force in x direction
"F_x=-kv_x^2=ma_x"
So acceleration
"a_x=\\frac{dv_x}{dt}=-\\frac{ kv_x^2}{m}"
So using integration limits
"\\int_{v_0cos\\alpha}^{v_x}\\frac{dv_x}{v_x^2}=\\int _0^t\\frac{-kdt}{m}"
So we get
"[\\frac{1}{v_x}]_{v_0cos\\alpha}^{v_0}=-\\frac{kt}{m}"
So in terms of vx and t
"v_x=-\\frac{m}{kt}\\\\v_x\\propto\\frac{1}{t}"
Comments
Leave a comment