Question #160909

A simple pendulum has a period of 2.5 s. What is its period if its length is made four times larger?

Expert's answer

The period of the pendulum can be written as follows:


T=2πLg.T=2\pi \sqrt{\dfrac{L}{g}}.

If the length of the pendulum is four times larger, then the period will be:


Tnew=2π4Lg=22πLg=2T,T_{new}=2\pi \sqrt{\dfrac{4L}{g}}=2\cdot2\pi \sqrt{\dfrac{L}{g}}=2T,Tnew=22.5 s=5 s.T_{new}=2\cdot2.5\ s=5\ s.
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