Answer to Question #160907 in Classical Mechanics for Eva

Question #160907
An object of mass 0.40kg, hanging from a spring with a spring constant of 8.0N/m, is set into an up-and down simple harmonic motion. What is the magnitude of the acceleration of the object when it is at its maximum displacement of 0.10m?
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Expert's answer
2021-02-10T10:11:17-0500

When the object is at its maximum displacement, the magnitude of the force exerted on it by the spring can be written as follows:


F=kxmax=8.0 ms20.1 m=0.8 N.F=kx_{max}=8.0\ \dfrac{m}{s^2}\cdot0.1\ m=0.8\ N.

Finally, we can find the acceleration of the object from the Newton's Second Law of Motion:


a=Fm=0.8 N0.4 kg=2 ms2.a=\dfrac{F}{m}=\dfrac{0.8\ N}{0.4\ kg}=2\ \dfrac{m}{s^2}.

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