Question

Water (specific heat Cv = 4,2 kJ/kg.K) is being heated by a 1500 W heater. What is the rate of change in temperature of 1 kg of the water?

Answer 1

$Q=mC_v\Delta{T}$

$\Delta{T}=\frac{Q}{mC_v};m=1kg;C_v=4200\frac{J}{kg*K}$

$\Delta{T}=\frac{1500}{4200}\approx0.357 K/s$

Answer:0.357K/s