Question

A metal cylinder of mass 4kg vibrates harmonically with an amplitude of 0.25m and period of 2second. Calculate 1)Frequency 2)its maximum speed and speed when y=0.15m

Answer 1

Answer

1) frequency is inverse of time period

$f=\frac{1}{T}=\frac{1}{2}=0.5Hz.$

2) SHM equation is given by

$y=y_0sin\omega t$

Velocity

$v=v_0cos\omega t$

Where $v_0$ is $y_0 \omega$

Maximum velocity

$v=v_0=y_0\omega$

$=0.15\times2\pi\times0.5$

=0.471 m/s