Question

A small piston of a hydraulic press has an area of 20.0 cm2. If the applied force to the piston is

75.0 N, what must the area of the connected large piston be to exert a force of 6550 N?

Answer 1

Given:

$A_1=20.0\:\rm cm^2$

$F_1=75.0\:\rm N$

$F_2=6550\:\rm N$

The Pascal's principle says

$$\frac{F_1}{A_1}=\frac{F_2}{A_2}$$

Hence

$$A_2=A_1\frac{F_2}{F_1}=\rm 20.0\times\frac{6550}{75.0}=1750\: cm^2$$

Answer: $\rm 1750\: cm^2$