A small piston of a hydraulic press has an area of 20.0 cm2. If the applied force to the piston is
75.0 N, what must the area of the connected large piston be to exert a force of 6550 N?
Given:
"A_1=20.0\\:\\rm cm^2"
"F_1=75.0\\:\\rm N"
"F_2=6550\\:\\rm N"
The Pascal's principle says
"\\frac{F_1}{A_1}=\\frac{F_2}{A_2}"Hence
"A_2=A_1\\frac{F_2}{F_1}=\\rm 20.0\\times\\frac{6550}{75.0}=1750\\: cm^2"Answer: "\\rm 1750\\: cm^2"
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