Question

When a ball is released freely, it falls to the ground at 25 degrees. What is the horizontal scale and maximum height of the ball?

Answer 1

$$\tan{25}=\frac{v_y}{v_x}=\frac{gt}{v_x}$$

$$\frac{x}{H}=\frac{v_xt}{0.5gt^2}=\frac{2}{\tan{25}}=4.3$$