By defenition∣A×B∣=ABsinα,|A×B|=ABsin\alpha,∣A×B∣=ABsinα,
Area of parallelogram equals two areas of triangles 12ABsinα,\frac 12 AB sin \alpha,21ABsinα, i.e. ABsinα,ABsin\alpha,ABsinα, where α\alphaα is angle befween A and B.
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