Answer to Question #155352 in Classical Mechanics for Xoxo

Question #155352
  1. Let the force of gravity to be constant for small distances above the surface of the earth. A body is dropped from rest at a height h above the earth surface. What will be its kinetic energy just before it strikes the ground?   
1
Expert's answer
2021-01-14T10:39:45-0500

Answer

A body is dropped from rest at a height h above the earth surface. its kinetic speed just before it strikes the ground is given

V=2g(Re+h)V=\sqrt{2g(R_e+h) }

Where Re is radius of earth.

Now kinetic energy is given by

KE=m×2g(Re+h)2=m×g(Re+h)KE=\frac{m\times2g(R_e+h) }{2}\\=m\times g(R_e+h)

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