Answer to Question #154182 in Classical Mechanics for Zeke

Question #154182

A loaded wagon, the mass of which is 6000 kg, rolls to the right at

2.0 m / s when it collides with an empty freight car, weighing 3000 kg, rolling to the left on the same track at 3.0 m / s. If the cars remain tied together after the collision, what is the speed and direction of the pair of cars after the collision?


1
Expert's answer
2021-01-12T12:15:03-0500

Applying the law of conservation of momentum, we have:


m1v1im2v2i=(m1+m2)vf,m_1v_{1i}-m_2v_{2i}=(m_1+m_2)v_f,vf=m1v1im2v2i(m1+m2),v_f=\dfrac{m_1v_{1i}-m_2v_{2i}}{(m_1+m_2)},vf=6000 kg2.0 ms3000 kg3.0 ms(6000 kg+3000 kg)=0.33 ms.v_f=\dfrac{6000\ kg\cdot 2.0\ \dfrac{m}{s}-3000\ kg\cdot 3.0\ \dfrac{m}{s}}{(6000\ kg+3000\ kg)}=0.33\ \dfrac{m}{s}.


The sign plus means that the pair of cars after the collision move to the right.

Answer:

vf=0.33 ms,v_f=0.33\ \dfrac{m}{s}, to the right.


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