A plane starts from rest and reaches a speed of 600m/s by the end of the runway in 10 seconds. What is the acceleration of the plan? What is the distance of the runway?
V0=0;V1=600V_0=0;V_1=600V0=0;V1=600
a=V1−V0t=60010=60a=\frac{V_1-V_0}{t}=\frac{600}{10}=60a=tV1−V0=10600=60
s=V0t+at22=0∗10+60∗1002=3000s=V_0t+\frac{at^2}{2}=0*10+\frac{60*100}{2}=3000s=V0t+2at2=0∗10+260∗100=3000
Answer: a = 60 m/s2;s = 3000 m
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