Answer to Question #154014 in Classical Mechanics for Hussain Darboe

Question

A U-Tube contains some mercury of a relative density of 13.6, kerosine of a relative density of 0.8 is poured into one arm of the U-Tube until the height of mercury in that arm is reduced by 1.5cm. Calculate the height of kerosine?

Answer 1

$$(ρgh) _ w ​ =(ρgh) _ m ​$$

$$(103)(9.81)(0.136)−(13600)(9.81)(2y)=0\\y=0.005\ m = 5\ mm$$