Charge needed within a unit sphere centуred at the origin for producing a potential field V=-6r^5/E0 where r less than or equal to 1
Solution
We know relationship between electric field and potential is given by
E=−dVdr=30r4ϵ0=q4πϵ0r2E=-\frac{dV}{dr}=\frac{30r^4}{\epsilon_0}=\frac{q}{4\pi \epsilon_0 r^2}E=−drdV=ϵ030r4=4πϵ0r2q
Using r=1meter
q=12pCq=12pCq=12pC
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