Question

The radius of a bowling ball is 0.11 m and its mass is 7.26 kg. What is its density
(a) in kg m−3?
(b) in g cm−3?

Answer 1

Answer

a) density is given by

$d=\frac{m}{V}=\frac{7.26}{4/3\pi R^3}$

$=\frac{7.26}{1.33\times3.14\times(0.11)^3}$

$=1,305.75$ Kg/m³

b) in gram and centimeter

$d=1305.75\times\frac{1000}{1000000}=1.3g/cm^3$