Answer to Question #152337 in Classical Mechanics for sam

Question

A 2.00 kg block is pushed against a spring with negligible mass and stiffness k=400N/m, compressing it by 0.220 m.
When the block is released, it moves along a frictionless, horizontal surface and then up a frictionless incline with slope 37o (see figure below). 

Answer 1

Answer

Maximum height attain by block on inclined plain can be given as

$\frac{1}{2}Kx^2=mgh$

By putting the value

$\frac{1}{2}(400) (0.220) ^2=2\times 9.8\times h\\h=0.5m$

So maximum height attain by block on inclined plane is 0.5m.