A movie stuntman with a mass of 90 kg stands on a stationary 1 kg skateboard. An actor throws a 3.4 kg brick at the stuntman who catches it. The brick is travelling at 4.1 m s−1 when caught.
Answer
By applying momentum conservation
"M_{brick}v_1=(M_{stuntmen}+m_{skateboard}+M_{brick}) v"
By putting value
"3.4\\times4.1=(90+1+3.4) v"
"v=0.15m\/s"
So velocity of stuntmen after caught up the brick will be 0.15m/s
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