Answer to Question #150861 in Classical Mechanics for Emma

Question

Franz is standing on a hill throwing a snowball at a target, as illustrated in the diagram
below. The centre of the target is located 2.0 m below his hand.
Franz tosses the snowball with a velocity of 4.2 m/s at an angle of 50° above the
horizontal. The snowball hits the centre of the target, much to Franz’s delight. What is the horizontal distance between Franz and the target?

Answer 1

$$y=h+vt\sin{50}-0.5gt^2\\0=2+4.2\sin{50}t-0.5(9.8)t^2\\t=1.05\ s$$

$$x=vt\cos{50}=(4.2)(1.05)\cos{50}=2.8\ m$$