Answer to Question #150824 in Classical Mechanics for Subhajit Das

Question

Mass on wedge*
A 45◦ wedge is pushed along a table with constant acceleration A.
A block of mass m slides without friction on the wedge. Find the
block’s acceleration. Gravity is directed down

Answer 1

Answer

The wedge is at 45° angle so acceleration due to constant acceleration

$a_1=A/2$

Now due to gravity

$a_2=g/2$

Therefore acceleration on block is

$a=(a_1+a_2) /2=(A+g) /2$