Answer to Question #150105 in Classical Mechanics for John P

Question

Two forces act on a 17.2 kg object, A= 27N @27° and B= 43N @ x°. The direction of B is __ degrees if the acceleration is 3.79477 m/s^2 @ 0°

Answer 1

$$F=ma=(17.2)(3.79477)=65.27\ N$$

$$F=27\cos{27}+43\cos{x}\\ x=\arccos{\frac{65.27-27\cos{27}}{43}}=16.58\degree$$