Answer to Question #150105 in Classical Mechanics for John P

Question #150105
Two forces act on a 17.2 kg object, A= 27N @27° and B= 43N @ x°. The direction of B is __ degrees if the acceleration is 3.79477 m/s^2 @ 0°
1
Expert's answer
2020-12-14T07:16:03-0500
F=ma=(17.2)(3.79477)=65.27 NF=ma=(17.2)(3.79477)=65.27\ N

F=27cos27+43cosxx=arccos65.2727cos2743=16.58°F=27\cos{27}+43\cos{x}\\ x=\arccos{\frac{65.27-27\cos{27}}{43}}=16.58\degree


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