Question #150091

A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m from where it was launched.

Expert's answer

Answer

Vertical displacement can be given as

10=12gt2t=209.8=1.4s10=\frac{1}{2}gt^2\\t=\sqrt{\frac{20}{9.8}}=1.4s

Horizontal displacement can be given as

15=v0tv0=151.4=10.7m/s15=v_0t\\v_0=\frac{15}{1.4}=10.7m/s

So initial horizontal velocity is 10.7m/s







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