Answer
Vertical displacement can be given as
10=12gt2t=209.8=1.4s10=\frac{1}{2}gt^2\\t=\sqrt{\frac{20}{9.8}}=1.4s10=21gt2t=9.820=1.4s
Horizontal displacement can be given as
15=v0tv0=151.4=10.7m/s15=v_0t\\v_0=\frac{15}{1.4}=10.7m/s15=v0tv0=1.415=10.7m/s
So initial horizontal velocity is 10.7m/s
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