Answer to Question #150091 in Classical Mechanics for dina

Question

A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m from where it was launched.

Answer 1

Answer

Vertical displacement can be given as

$10=\frac{1}{2}gt^2\\t=\sqrt{\frac{20}{9.8}}=1.4s$

Horizontal displacement can be given as

$15=v_0t\\v_0=\frac{15}{1.4}=10.7m/s$

So initial horizontal velocity is 10.7m/s