Solution
Motion law for this body is given
s=2t+t2s=2t+t^2s=2t+t2
Now differentiate with respect to t
v=dsdt=2+2tv=\frac{ds}{dt}=2+2tv=dtds=2+2t
Again differentiate with respect to t
Then acceleration
a=dvdt=d2sdt2=2a=\frac{dv}{dt}=\frac{d^2s}{dt^2}=2a=dtdv=dt2d2s=2
So force acting on the body.
F=ma=2×2=4NF=ma=2\times 2=4NF=ma=2×2=4N
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