Question #148423
a wood block of mass m=300g rests on a larger wood block of mass m=4kg that rests a wooden table.the coefficients of static and kinetic friction between al surfaces are 0.4 and 0,2 respectively.a horizontal force ,f, is applied to the lower block
1
Expert's answer
2020-12-04T11:16:13-0500

Answer

Mass of upper block(m) =0.3kg

Mass of lower block(M) =4kg

If horizontal F force applied on lower block then it's minimum value should be

F=μ1(m+M)g+μ2mgF=0.2(0.3+4)×9.81+0.4×0.3×9.81F=9.61NF=\mu _1(m+M) g+\mu_2mg\\F=0.2(0.3+4) \times 9.81+0.4\times 0.3\times9.81\\F=9.61N


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