Answer
Mass of upper block(m) =0.3kg
Mass of lower block(M) =4kg
If horizontal F force applied on lower block then it's minimum value should be
F=μ1(m+M)g+μ2mgF=0.2(0.3+4)×9.81+0.4×0.3×9.81F=9.61NF=\mu _1(m+M) g+\mu_2mg\\F=0.2(0.3+4) \times 9.81+0.4\times 0.3\times9.81\\F=9.61NF=μ1(m+M)g+μ2mgF=0.2(0.3+4)×9.81+0.4×0.3×9.81F=9.61N
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