Answer
Length of ramp
"=\\sqrt{5^2+1.3^2}=5.17m"
Net work done is equal to change in potential energy
"W=U=mgh"
"=15\\times10\\times1.3"
"W=195J"
Total work done
"W=Fd=132\\times1.57"
"W=682.44J"
Efficiency is given by
"\\eta=\\frac{195}{682.44}\\times100=29.12\\%"
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