Answer
Work done in lifting mass = force × distance moved
W = weight of body × distance moved
W= 0.5"\\times9.8\\times0.8"
W=3.92J
So power
"P=\\frac{W}{t}=\\frac{3.92}{20}=0.196 Watts"
b) efficiency
"\\eta=\\frac{work\\space done}{suppied\\space energy}=\\frac{3.92}{12}"
"\\eta=33\\%"
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