Question

A ball is thrown vertically upwards at a speed of 11.0 m s−1.
What is the maximum height it reaches?

Answer 1

Solution

Using equation of motion

$v^2=u^2+2as$

$(0)^2=(11)^2-2gH$

At maximum height velocity is zero.

$H=\frac{121}{2\times9.8}=6.17m$